Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 13


$$\frac{1}{16} \sinh (8 x-18) d x-\frac{1}{2} x+C$$

Work Step by Step

\begin{aligned} \int \sinh ^{2}(4 x-9) d x &=\frac{1}{2} \int(\cosh (8 x-18)-1) d x \\ &=\frac{1}{16} \sinh (8 x-18) d x-\frac{1}{2} x+C\end{aligned}
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