Answer
$$\frac{1}{16} \sinh (8 x-18) d x-\frac{1}{2} x+C$$
Work Step by Step
\begin{aligned} \int \sinh ^{2}(4 x-9) d x &=\frac{1}{2} \int(\cosh (8 x-18)-1) d x \\ &=\frac{1}{16} \sinh (8 x-18) d x-\frac{1}{2} x+C\end{aligned}
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 8 - Techniques of Integration - 8.4 Integrals Involving Hyperbolic and Inverse Hyperbolic Functions - Exercises - Page 415: 13
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