## Calculus (3rd Edition)

$\lim\limits_{t \to 3}\frac{h(t)}{t}=\lim\limits_{t \to 3}h(t)\times\lim\limits_{t \to 3}\frac{1}{t}=5$ Or $\lim\limits_{t \to 3}h(t)\times\frac{1}{\lim\limits_{t \to 3}t}=5$ $\implies \lim\limits_{t \to 3}h(t)\times\frac{1}{3}=5$ Which gives: $\lim\limits_{t \to 3}h(t)=5\times3=15$