Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 38


$\lim\limits_{t \to 3}\frac{h(t)}{t}=\lim\limits_{t \to 3}h(t)\times\lim\limits_{t \to 3}\frac{1}{t}=5$ Or $\lim\limits_{t \to 3}h(t)\times\frac{1}{\lim\limits_{t \to 3}t}=5$ $\implies \lim\limits_{t \to 3}h(t)\times\frac{1}{3}=5$ Which gives: $\lim\limits_{t \to 3}h(t)=5\times3=15$

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