Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 19


$=\dfrac {1}{5}=0.2$

Work Step by Step

$\lim _{x\rightarrow -1}\dfrac {x}{x^{3}+4x}=\dfrac {-1}{\left( -1\right) ^{3}+4\times \left( -1\right) }=\dfrac {-1}{-1+\left( -a\right) }=\dfrac {-1}{-5}=\dfrac {1}{5}=0.2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.