Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 14


$=\dfrac {3}{7}$

Work Step by Step

$\lim _{z\rightarrow 9}\dfrac {\sqrt {z}}{z-2}=\dfrac {\sqrt {9}}{9-2}=\dfrac {3}{7}$
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