Answer
$=\dfrac {3}{7}$
Work Step by Step
$\lim _{z\rightarrow 9}\dfrac {\sqrt {z}}{z-2}=\dfrac {\sqrt {9}}{9-2}=\dfrac {3}{7}$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 14
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