Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises: 12

Answer

$6$

Work Step by Step

$\lim _{x\rightarrow \dfrac {1}{2}}\left( 4x+1\right) \left( 6x-1\right) =\left( 4\times \dfrac {1}{2}+1\right) \left( 6\times \dfrac {1}{2}-1\right) =3\times 2=6$
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