## Calculus (3rd Edition)

Published by W. H. Freeman

# Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 18

#### Answer

$4$

#### Work Step by Step

$\lim _{w\rightarrow 7}\dfrac {\sqrt {w+2}+1}{\sqrt {w-3}-1}=\dfrac {\sqrt {7+2}+1}{\sqrt {7-3}-1}=\dfrac {3+1}{2-1}=\dfrac {4}{1}=4$

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