Answer
$4$
Work Step by Step
$\lim _{w\rightarrow 7}\dfrac {\sqrt {w+2}+1}{\sqrt {w-3}-1}=\dfrac {\sqrt {7+2}+1}{\sqrt {7-3}-1}=\dfrac {3+1}{2-1}=\dfrac {4}{1}=4$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 18
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