Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 17


$=\dfrac {1}{5}=0.2$

Work Step by Step

$\lim _{y\rightarrow 4}\dfrac {1}{\sqrt {6y+1}}=\dfrac {1}{\sqrt {6\times 4+1}}=\dfrac {1}{\sqrt {25}}=\dfrac {1}{5}=0.2$
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