Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises - Page 59: 29


$=\dfrac {1}{16}$

Work Step by Step

$\lim _{x\rightarrow -4}\dfrac {g\left( x\right) }{x^{2}}=\dfrac {\lim _{x\rightarrow -4}g\left( x\right) }{x^{2}}=\dfrac {1}{\left( -4\right) ^{2}}=\dfrac {1}{16}$
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