Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 2 - Limits - 2.3 Basic Limit Laws - Exercises: 30

Answer

$=\dfrac {-2}{3}$

Work Step by Step

$\lim _{x\rightarrow -4}\dfrac {f\left( x\right) +1}{3g\left( x\right) -9}=\dfrac {\lim _{x\rightarrow -4}f\left( x\right) +1}{3\lim _{x\rightarrow -4}g\left( x\right) -9}=\dfrac {3+1}{3\times 1-9}=\dfrac {4}{-6}=\dfrac {-2}{3}$
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