Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - Chapter Review Exercises - Page 591: 3



Work Step by Step

We have $$ \lim _{n \rightarrow \infty}\left(5 a_{n}-2 a_{n}^{2}\right)= 5\lim _{n \rightarrow \infty} a_{n}-2( \lim _{n \rightarrow \infty} a_{n})^{2} \\ =5 \times 2-2\times 2^2=10-8=2. $$
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