Answer
$2$
Work Step by Step
We have $$
\lim _{n \rightarrow \infty}\left(5 a_{n}-2 a_{n}^{2}\right)=
5\lim _{n \rightarrow \infty} a_{n}-2( \lim _{n \rightarrow \infty} a_{n})^{2} \\
=5 \times 2-2\times 2^2=10-8=2.
$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 11 - Infinite Series - Chapter Review Exercises - Page 591: 3
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