Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 11 - Infinite Series - Chapter Review Exercises - Page 591: 6



Work Step by Step

We have $$ \lim _{n \rightarrow \infty}\cos (\pi a_n)= \cos (\pi \lim _{n \rightarrow \infty}a_n) \\ =\cos (2\pi )=1 $$
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