Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises - Page 301: 7

Answer

$=\frac{2(25-x^2)^{3/2}}{3}+C$

Work Step by Step

$let$ $25-x^2=u$ $du=-2x$ $dx$ $\int u^{1/2}$$du$ $=\int (25-x^2)^{1/2}$$-2x$ $dx$ $=\frac{2(25-x^2)^{3/2}}{3}+C$
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