Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises: 26

Answer

$\frac{3}{20}(5x^2)^{\frac{2}{3}}+C$

Work Step by Step

let $5x^2=u$ $du=10x$ $dx$ $\int \frac{x}{(5x^2)^{\frac{1}{3}}}dx$ $=\frac{1}{10} \int \frac{du}{u^{\frac{1}{3}}}$ $=\frac{1}{10}(\frac{3}{2}u^{\frac{3}{2}})+C$ $=\frac{3}{20}(5x^2)^{\frac{2}{3}}+C$
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