Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises: 34

Answer

$-\frac{\cos(4x)}{4}+C$

Work Step by Step

$\int \sin(4x)dx$ let $u=4x$ $4dx=du$ $dx=\frac{1}{4}du$ $\int \sin(4x)dx$ $=\frac{1}{4} \int \sin(u)du$ $=\frac{1}{4}-\cos(u)+C$ $=-\frac{\cos(4x)}{4}+C$
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