Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises - Page 301: 33

Answer

$-\cos\hspace{0.5mm}\pi x+C$

Work Step by Step

$\int\pi\sin\hspace{0.5mm}\pi x\hspace{0.5mm}dx$ Let $u=\pi x\hspace{8mm}du=\pi dx\hspace{8mm}dx=\frac{du}{\pi}$ $\int\pi\sin\hspace{0.5mm}\pi x\hspace{0.5mm}dx=\int\pi\sin\hspace{0.5mm}u\hspace{0.5mm}\frac{du}{\pi}=\int\sin{u}du=-\cos{u}+C$ $=-\cos\hspace{0.5mm}\pi x+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.