Answer
$\frac{x^3}{3}-\frac{1}{9x}+C$
Work Step by Step
$\int\left[x^2+\frac{1}{(3x)^2}\right]dx=\int x^2dx+\int\frac{1}{9x^2}dx=\frac{x^3}{3}-\frac{1}{9x}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 24
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