Answer
$-4^{-1}(4x^3-9)^{-2} +C$
Work Step by Step
let $4x^3-9=u$
$du=12x^2$ $dx$
$\int \frac{6x^2}{(4x^3-9)^3}dx$
$=2 \int \frac{du}{u^3} $
$=2 (-\frac{1}{2} u^{-2})+C$
$=-4^{-1}(4x^3-9)^{-2} +C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 20
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