Answer
$-\frac{(1+x^4)^{-1}}{4}+C$
Work Step by Step
$let$ $1+x^4=u$
$du=4x^3$ $dx$
$\int u^{-2}$ $du$
$=\frac{1}{4}\int (1+x^4)^{-2}$$4x^3$ $dx$
$=\frac{1}{4}(\frac{3(1+x^4)^{-1}}{-1})+C$
$=-\frac{(1+x^4)^{-1}}{4}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 4 - Integration - 4.5 Exercises - Page 301: 18
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
