Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 4 - Integration - 4.5 Exercises: 19



Work Step by Step

$let$ $1+x^3=u$ $du=3x^2$ $dx$ $\int$$u^{-2}$ $du$ $=\frac{1}{3}\int$$(1+x^3)^{-2}$ $(3x^2)$ $dx$ $=\frac{1}{3}(\frac{(1+x^{3})^{-1}}{-1})+C$ $=-\frac{1}{3(1+x^{3})}+C$
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