Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 14 - Multiple Integration - 14.2 Exercises - Page 983: 5

Answer

$8$

Work Step by Step

Let us suppose that $I=\int_{0}^2 \int_{0}^{1} (1+2x+2y) \ dy \ dx$ Next, we will solve the integral as follows: $I=\int_{0}^2 [\int_{0}^{1} (1+2x+2y) \ dy] \ dx$ or, $=\int_{0}^2 [(y+2xy+\dfrac{2y^2}{2})]_{0}^{1} \ dx$ or, $=\int_{0}^2 (2x+2) \ dx$ or, $=[2x+\dfrac{2x^2}{2}]_0^2$ or, $=(2)(2)+\dfrac{2(2)^2}{2}$ or, $=8$
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