Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5: 8

Answer

$f'(x)=2x\sec x+(x^2+1)(\sec x\tan x)$

Work Step by Step

$f(x)=(x^2+1)secx$ $f'(x)=\frac{d}{dx}(x^2+1)\times{secx}+(x^2+1)\times{\frac{d}{dx}(secx)}$ $f'(x)=(2x)\times{secx}+(x^2+1)\times{(secxtanx)}$ $f'(x)=2x\sec x+(x^2+1)(\sec x\tan x)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.