Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5: 12

Answer

$f'(x)=−\csc^3x−\cot^2x\csc x$

Work Step by Step

$f(x)=cscxcotx$ $f'(x)=\frac{d}{dx}(cscx)\times{cotx}+cscx\times\frac{d}{dx}(cot)$ $f'(x)=\frac{d}{dx}(cscx)\times{cotx}+cscx\times\frac{d}{dx}(cot)$ $f'(x)=(−csc^2x)\times{cscx}+(−cotx)\times{cscxcotx}$ $f'(x)=−\csc^3x−\cot^2x\csc x$
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