Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5: 16

Answer

$f'(x)=0$

Work Step by Step

$f(x)=sec^2x-tan^2x$ Recall that $(tan^2x+1\equiv sec^2$) $f(x)=1$ $f'(x)=0$
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