Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5: 3

Answer

$f'(x)=4x^{2}\sin x-8x\cos x$

Work Step by Step

$f(x)=-4x^{2}cos x$ $f'(x)=-4x^{2}\frac{d}{dx}[cosx]+cosx\frac{d}{dx}[-4x^{2}]$ $f'(x)=-4x^{2}(-\sin x)+\cos x(-4)(2)x$ $f'(x)=4x^{2}\sin x-8x\cos x$
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