Answer
$f'(x)=\sec x\tan^2x+\sec^3x$
Work Step by Step
$f(x)=secxtanx$
$f'(x)=\frac{d}{dx}(secx)\times{tanx}+secx\times\frac{d}{dx}(tanx)$
$f'(x)=secxtanx\times{tanx}+secx\times{sec^2x}$
$f'(x)=\sec x\tan^2x+\sec^3x$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5 - Page 151: 11
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