Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.5 Derivatives of Trigonometric Functions - Exercises Set 2.5: 11

Answer

$f'(x)=\sec x\tan^2x+\sec^3x$

Work Step by Step

$f(x)=secxtanx$ $f'(x)=\frac{d}{dx}(secx)\times{tanx}+secx\times\frac{d}{dx}(tanx)$ $f'(x)=secxtanx\times{tanx}+secx\times{sec^2x}$ $f'(x)=\sec x\tan^2x+\sec^3x$
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