Answer
$\frac{d^2y}{dx^2}=5\cos x-x\sin x$
Work Step by Step
$y=xsinx-3cosx$
$\frac{dy}{dx}=(sinx+x\times{cosx})-3(-sinx)$
$\frac{dy}{dx}=(sinx+xcosx)+3sinx$
$\frac{dy}{dx}=4sinx+xcosx$
$\frac{d^2y}{dx^2}=4(cosx)+(cosx+x\times{(-sinx)})$
$\frac{d^2y}{dx^2}=4cosx+(cosx-xsinx)$
$\frac{d^2y}{dx^2}=5\cos x-x\sin x$