Answer
False
Work Step by Step
Per Theorem $14.3,3,$ the volume of a double integral is evaluated as
\[
\int_{\alpha}^{\beta} \int_{r_{1}(\theta)}^{r_{2}(\theta)} r \mathrm{d} r \mathrm{d} \theta
\]
The $\mathbf{r}$ is next to $\mathrm{d} r .$ The question's double integral doesn't contain the needed extra $r,$ so it's incorrect.