Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 30


$$ 2.58\times10^8 \ kg .m^2 /s^2 $$

Work Step by Step

The kinetic energy is given by $$ K.E.=\frac{1}{2}mv^2=\frac{1}{2}(2.87\times10^6)(13.4)^2= 2.58\times10^8 \ kg .m^2 /s^2 $$
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