Answer
$$ 2.58\times10^8 \ kg .m^2 /s^2
$$
Work Step by Step
The kinetic energy is given by
$$
K.E.=\frac{1}{2}mv^2=\frac{1}{2}(2.87\times10^6)(13.4)^2= 2.58\times10^8 \ kg .m^2 /s^2
$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 30
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