Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 22


$$0.044 \ N/m^2$$

Work Step by Step

We have $$ \frac{0.497\ N }{ (1.4\ m)(8.0\ m)}=0.0443\ N/m^2 .$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$0.0443\ N/m^2=0.044 \ N/m^2$$
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