Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 10

Answer

$$48 \times 10^{-6}\ m^3.$$

Work Step by Step

We have $$(0.045 \ m)(0.0292 \ m)(0.0365 \ m)= 0.000048 \ m^3.$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$(0.045 \ m)(0.0292 \ m)(0.0365 \ m)= 48 \times 10^{-6}\ m^3.$$
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