Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 13


$$35\ A^2 \Omega$$

Work Step by Step

We have $$ (0.480 \ A)^2(150 \ \Omega )=34.56\ A^2 \Omega .$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$34.56\ A^2 \Omega= 35\ A^2 \Omega$$
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