Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 17

Answer

$$40\ m$$

Work Step by Step

We have $$ 1520\ m^2 \div 40\ m=38\ m .$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$38\ m=40\ m$$
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