# Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 11

$$4.7 \times 10^9 \ m^3.$$

#### Work Step by Step

First, we have $$(2460 \ m)(960 \ m)(1970\ m)=4652352000 \ m^3$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$(2460 \ m)(960 \ m)(1970\ m)=4.7 \times 10^9 \ m^3.$$

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