## Elementary Technical Mathematics

$$39,800,000 \ in^3$$
We have $$(46\bar{0} \ in)(235 \ in )(368 \ in)=39780800 \ in^3 .$$ Now, round this product to three significant digits, which is the accuracy of the least accurate measurement (in fact all the measurements have the same accuracy of 3). That is, $$39780800 \ in=39,800,000 \ in^3$$