Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 12


$$39,800,000 \ in^3$$

Work Step by Step

We have $$ (46\bar{0} \ in)(235 \ in )(368 \ in)=39780800 \ in^3 .$$ Now, round this product to three significant digits, which is the accuracy of the least accurate measurement (in fact all the measurements have the same accuracy of 3). That is, $$39780800 \ in=39,800,000 \ in^3$$
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