Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 15


$$2500\ in^2$$

Work Step by Step

We have $$ 62,500 \ in^3 \div 25 \ in=2500\ in^2 .$$ There is no need to round this product to two significant digits because it has already two significant digits ("2" and "5").
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