Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.6 - Multiplication and Division of Measurements - Exercise - Page 188: 25


$$4.0\ g /cm^3$$

Work Step by Step

We have $$ \frac{140\ g }{ (3.2 \ cm)(1.7 \ cm)(6.4 \ cm)}=4.021\ g /cm^3 .$$ Now, round this product to two significant digits, which is the accuracy of the least accurate measurement. That is, $$4.021\ g /cm^3=4.0\ g /cm^3$$
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