Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 473: 60


$x=0$ or $x=2$ or $x=-2$

Work Step by Step

$ x^{3}-4x=0\qquad$...factor out the common term, $x$. $ x(x^{2}-4)=0\qquad$...recognize a difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $ x(x-2)(x+2)=0\qquad$...apply the principle of zero products. $x=0$ $x-2=0$ $x=2$ $x+2=0$ $x=-2$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $0,2$ and $-2$.
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