Answer
$x=-2$ or $x=-3$
Work Step by Step
$(x-3)(x+8)=-30\qquad$...apply the FOIL method.
$ x^{2}+8x-3x-24=-30\qquad$... add $30$ to both sides.
$x^{2}+5x+6=0$
... Searching for two factors of $ac=6$ whose sum is $b=5,$
we find$\qquad 2$ and $3.$
Rewrite the middle term and factor in pairs:
$x^{2}+2x+3x+6=0$
$x(x+2)+3(x+2)=0$
$(x+2)(x+3)=0\qquad$...apply the principle of zero products.
$x+2=0$ or $x+3=0$
$x=-2$ or $x=-3$
Type the equation into a graphing utility and see
that the graph intercepts the x-axis at $-2$ and $-3$.
