Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 473: 50

Answer

$x=-4$ or $x=-\displaystyle \frac{2}{3}$

Work Step by Step

$(x+3)(3x+5)=7\qquad$...apply the FOIL method. $ 3x^{2}+5x+9x+15=7\qquad$... add $-7$ to both sides. $3x^{2}+14x+8=0$ ... Searching for two factors of $ac=24$ whose sum is $b=14,$ we find$\qquad 12$ and $2.$ Rewrite the middle term and factor in pairs: $3x^{2}+12x+2x+8=0$ $3x(x+4)+2(x+4)=0$ $(x+4)(3x+2)=0\qquad$...apply the principle of zero products. $x+4=0$ or $3x+2=0$ $x=-4$ or $ 3x=-2\qquad$...divide the second expression with $3$. $x=-4$ or $x=-\displaystyle \frac{2}{3}$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $-4$ and $-\displaystyle \frac{2}{3}$.
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