Answer
$x=-6$ or $x=3$
Work Step by Step
$(x-1)(x+4)=14\qquad$...apply the FOIL method.
$ x^{2}+4x-x-4=14\qquad$... add $-14$ to both sides.
$x^{2}+3x-18$
... Searching for two factors of $ac=-18$ whose sum is $b=3,$
we find$\qquad 6$ and $-3.$
Rewrite the middle term and factor in pairs:
$x^{2}+6x-3x-18=0$
$x(x+6)-3(x+6)=0$
$(x+6)(x-3)=0\qquad$...apply the principle of zero products.
$x+6=0$ or $x-3=0$
$x=-6$ or $x=3$
Type the equation into a graphing utility and see
that the graph intercepts the x-axis at $-6$ and $3$.
