Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 473: 56


$w=\displaystyle \frac{8}{5}$

Work Step by Step

$ 25w^{2}=80w-64\qquad$...add $-80w+64$ to both sides of the expression. $ 25w^{2}-80w+64=0\qquad$...recognize a perfect square trinomial. $(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$ $(5w-8)^{2}=0$ $(5w-8)(5w-8)=0\qquad$...apply the principle of zero products. $5w=8$ $w=\displaystyle \frac{8}{5}$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $\displaystyle \frac{8}{5}$.
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