Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 473: 55


$w=\displaystyle \frac{3}{8}$

Work Step by Step

$ 64w^{2}=48w-9\qquad$...add $-48w+9$ to both sides of the expression. $ 64w^{2}-48w+9=0\qquad$...recognize a perfect square trinomial. $(A\pm B)^{2}=A^{2}\pm 2AB+B^{2}$ $(8w-3)^{2}=0$ $(8w-3)(8w-3)=0\qquad$...apply the principle of zero products. $8w=3$ $w=\displaystyle \frac{3}{8}$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $\displaystyle \frac{3}{8}$.
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