## Introductory Algebra for College Students (7th Edition)

Rewrite the equation so it is in standard form. x(x-3)=18 x$^2$-3x=18 x$^2$-3x-18=0 Factor the trinomial. (x+3)(x-6)=0 Set each variable factor as equal to zero and then isolate the variable to find the solutions. x+3=0 or x-6=0 x=-3 or x=6 Enter the equation into your graphing utility to observe that the graph crosses the x-axis at -3 and 6.