Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set: 31

Answer

x=$\frac{3}{2}$

Work Step by Step

Rewrite the equation in standard form. 4x$^2$=12x-9 4x$^2$-12x=-9 4x$^2$-12x+9=0 Factor the trinomial. (2x-3)(2x-3)=0 (2x-3)$^2$=0 Set each variable factor as equal to zero and then isolate the variable to find the solutions. 2x-3=0 2x=3 x=$\frac{3}{2}$ Enter the original equation into your graphing utility to observe that the graph crosses the x-axis at $\frac{3}{2}$.
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