Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.6 - Solving Quadratic Equations by Factoring - Exercise Set - Page 473: 59


$x=0$ or $x=6$ or $x=-6$

Work Step by Step

$ x^{3}-36x=0\qquad$...factor out the common term, $x$. $ x(x^{2}-36)=0\qquad$...recognize a difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $ x(x-6)(x+6)=0\qquad$...apply the principle of zero products. $x=0$ $x-6=0$ $x=6$ $x+6=0$ $x=-6$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $0,6$ and $-6$.
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