## Introductory Algebra for College Students (7th Edition)

$x=0$ or $x=6$ or $x=-6$
$x^{3}-36x=0\qquad$...factor out the common term, $x$. $x(x^{2}-36)=0\qquad$...recognize a difference of two squares: $a^{2}-b^{2}=(a-b)(a+b)$ $x(x-6)(x+6)=0\qquad$...apply the principle of zero products. $x=0$ $x-6=0$ $x=6$ $x+6=0$ $x=-6$ Type the equation into a graphing utility and see that the graph intercepts the x-axis at $0,6$ and $-6$.