Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 96

Answer

$x^2-y^2+10x+25$

Work Step by Step

First we use the Sum and Difference of Two Terms: $[(x+5)-y][(x+5)+y]$ $=(x+5)^2-y^2.$ Then we use the Square of a Binomial: $(x+5)^2-y^2$ $=x^2+10x+25-y^2$ $=x^2-y^2+10x+25.$
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