Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 93

Answer

$x^3+6x^2+12x+8$

Work Step by Step

We rewrite the given expression: $(x+2)^3=(x+2)^2(x+2)$ We use the Square of a Binomial rule: $(x+2)^2(x+2)$ $=(x^2+4x+4)(x+2).$ Then we use the FOIL rule: $(x^2+4x+4)(x+2)$ $=x^3+2x^2+4x^2+8x+4x+8$ $=x^3+6x^2+12x+8.$ Note: There is also a rule for the Cube of a Binomial: $(a+b)^3=a^3+3a^2b+3ab^2+b^3$
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