Answer
$x^3+12x^2+48x+64$
Work Step by Step
We rewrite the given expression:
$(x+4)^3=(x+4)^2(x+4)$
We use the Square of a Binomial rule:
$(x+4)^2(x+4)$
$=(x^2+8x+16)(x+4).$
Then we use the FOIL rule:
$(x^2+8x+16)(x+4)$
$=x^3+4x^2+8x^2+32x+16x+64$
$=x^3+12x^2+48x+64.$
Note: There is a rule for the Cube of a Binomial:
$(a+b)^3=a^3+3a^2b+3ab^2+b^3$
