Answer
$16x^4-72x^2+81$
Work Step by Step
First we apply the Sum and Difference of Two terms:
$[(2x+3)(2x-3)]^2$
$=[(2x)^2-3^2]^2$
$=(4x^2-9)^2$
Then we apply the Square of a Binomial:
$(4x^2-9)^2$
$=(4x^2)^2-2(4x^2)(9)+9^2$
$=16x^4-72x^2+81.$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 89
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