Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.3 - Special Products - Exercise Set - Page 368: 87

Answer

$6x+22$

Work Step by Step

The area of the shaded region is the area of the bigger rectangle minus the area of the smaller rectangle. Thus, the area $A_1$ of the bigger rectangle is: $(x+9)(x+3)=x^2+3x+9x+27$ $=x^2+12x+27.$ The area $A_2$ of the smaller rectangle is: $A_2=(x+5)(x+1)$ $=x^2+x+5x+5$ $=x^2+6x+5.$ Now we can calculate the shaded area: $A_1-A_2=(x^2+12x+27)-(x^2+6x+5)$ $=x^2+12x+27-x^2-6x-5$ $=6x+22.$
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